2y^2-8x=0

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Solution for 2y^2-8x=0 equation: 


Simplifying
2y2 + -8x = 0

Reorder the terms:
-8x + 2y2 = 0

Solving
-8x + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y2' to each side of the equation.
-8x + 2y2 + -2y2 = 0 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-8x + 0 = 0 + -2y2
-8x = 0 + -2y2
Remove the zero:
-8x = -2y2

Divide each side by '-8'.
x = 0.25y2

Simplifying
x = 0.25y2

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